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Leviafan [203]
3 years ago
5

If you drive 196 miles and use 7 gallons of gas, what is your rate of gas consumption?

Mathematics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

i think it 28

Step-by-step explanation:

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A group of students went on a field trip. The students were divided into 6 buses and each bus had less than 52 students. How man
Vikki [24]

Answer:

A maximum of 306

Step-by-step explanation:

You can estimate that since each bus had less than 52 students, that 51 were on each bus. 51 times 6=306

7 0
3 years ago
Read 2 more answers
3(x-4) = x + 14<br> How do you solve this equation
Dmitry_Shevchenko [17]

Answer:

x=13

Step-by-step explanation:

you have to isolate the variable

3(x-4)=x+14

distribute

3x-12=x+14

subtract 14 from each side

3x-26=x

subtract 3x from each side

-26=-2x

divide each side by -2

13=x

flip sides

x=13

hope this helps!!! :)

4 0
3 years ago
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Find the midpoint of the line segment with end coordinates of:(−1,7) and (3,−2)
SOVA2 [1]

Answer:

Step-by-step explanation:

mid point formula = (x1+x2/2 , y1+y2/2)

hence putt the values we get,

mid point = ( -1+3/2 , 7-2/2)

                 = (1 , 2.5)

5 0
3 years ago
If the equation of a line is given by y = 3.4x - 6.5, what is the slope of the line? (Remember, ONLY
Kobotan [32]
The slope of the line is 3.4
4 0
3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
4 years ago
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