Answer:
50
Step-by-step explanation:
she pays 10 in a flat fees and 2 dollars a minute so you multiply the 2 by 20 and add 10
<span>the sum of three consecutive odd integers is 69. Find the integers.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:</span>2x-1 + 2x+1 + 2x+3 = 69<span>
</span><span>6x + 3 = 69
2x + 1 = 23
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So 2x-1 = 21
And 2x+3 = 25
</span><span>let:
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69
</span>
<span>3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21
_______________________________________
x=21
x+2=23
x+4=25
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25..</span>
The answer is 156 because 50% of 104 is 52, and if you add the two together it's 156
Answer:
10x^2+13x+5
Step-by-step explanation:
(7x^2− 2x + 9) + (3x^2+ 15x − 4)
Combine like terms
(7x^2+3x^2− 2x+ 15x + 9 − 4)
10x^2+13x+5
6% of 100 is 6
100*70 = 7000
6*70 = 420
therefore
6% of 7000 = 0.06 * 7000= 420
