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dybincka [34]
4 years ago
5

For a snack, Sameer ate a plum with 32 calories and several strawberries with 4 calories each. If the total number of calories i

n Sameer’s snack was 56, how many strawberries did he eat?
Mathematics
2 answers:
Nina [5.8K]4 years ago
7 0
He would of ate 6  strawberries <span />
zhannawk [14.2K]4 years ago
4 0
He would have to eat 6 strawberries, you take the number of calories total (56) and subtract the Plum's calories (32) leaving 24 calories left, then you divide 24 by the total amout of calories the strawberries are (4) and get 6.
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The 5.52cm

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Ivan buys candy that costs $7 per pound. He will buy at most 9 pounds of candy. What are the possible amounts he will spend on c
Flauer [41]

Answer: 7c ≤ 63

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4 years ago
What is the volume of a Peerman with a base area of 8 ft.² and a height of 12 feet
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3 0
4 years ago
In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex
jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

          P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \mu = sample average efficiency = 85

            \sigma = sample standard deviation = 2

            n = sample of motors = 60

            \mu = population mean efficiency

<em>So, 95% confidence interval for the mean efficiency, </em>\mu<em> is ;</em>

P(-2.0009 < t_5_9 < 2.0009) = 0.95

P(-2.0009  < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.0009 ) = 0.95

P( -2.0009  \times {\frac{s}{\sqrt{n} } < {\bar X - \mu} < 2.0009  \times {\frac{s}{\sqrt{n} } ) = 0.95

P( \bar X -2.0009  \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.0009  \times {\frac{s}{\sqrt{n} } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.0009  \times {\frac{s}{\sqrt{n} } , \bar X +2.0009  \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 85 -2.0009  \times {\frac{2}{\sqrt{60} } , 85 +2.0009  \times {\frac{2}{\sqrt{60} } ]

                                                 = [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

8 0
3 years ago
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