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2 years ago

11

The product of 64 times 8 to the third power can be expressed as 2n. Find n.

1 answer:

solong [7]2 years ago

8 0

Is 2938281912 multiplied j382872

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Which values of <br> P<br> and <br> Q result in an equation with no solutions?<br> 83x+P=83x+Q

aleksandr82 [10.1K]

83x+P=83x+Q

subtract 83x from each side

P=Q

if P does not Q there are no solutions

the lines would be parallel and never intersect if Q does not equal P

6 0

2 years ago

Un carpintero quiere cortar una plancha de triple y de 1m de largo y 60 cm de ancho, en cuadrados lo más grandes posibles. El ca

Ugo [173]

Answer: $20\ cm$

Step-by-step explanation:

The first step to solve the exercise is to make the conversion from meters to centimeters.

Since $1\ m=100\ cm$ , then the dimensions of the wood board in centimeters are:

$Lenght=100\ cm\\\\Width=60\ cm$

Now, you must find the Greatest Common Factor (GCF). The steps are:

- Descompose 100 and 60 into their prime factors:

$100=2*2*5*5=2^2*5^2\\60=2*2*3*5=2^2*3*5$

- Multiply the commons with the lowest exponents:

$GCF=2^2*5\\\\GCF=4*5\\\\GCF=20$

Therefore, the side lenght of each square must be:

$s=20\ cm$

7 0

2 years ago

Please answer this question(picture included)

zlopas [31]

2xy^2 + 8y => 2y ( xy +4)

4 0

2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

A Ladder That Is 5 meters in length is resting on a branch of a tree and the base of the ladder is 3 meters from the tree on the

Stells [14]

Use the Pythagoras theorem:-

height = sqrt(5^2 - 3^2 ) = sqrt16 = 4 metres Answer.

5 0

3 years ago