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3 years ago

Find the product of (3.7 × 104) and 2.

1 answer:

7 0

If you would like to solve (3.7 * 104) * 2, you can calculate this using the following steps:

(3.7 * 104) * 2 = 384.8 * 2 = 769.6

The correct result would be 769.6.

You might be interested in

Write an equation of the line.

jarptica [38.1K]

Answer:

y + 5 = 0(x + 1)

y + 5 = 0

y = -5

standard form

0x + y = -5

7 0

3 years ago

in the backwaters of Kerala a boatman was throwing a Boat using a long pole of length 4.80 when he put the pole vertically into

Hitman42 [59]

Answer:

3.60m

Step-by-step explanation:

In backwaters of Kerala, a boatman was throwing a boat with a long pole which has a length of 4.80m

The boatman put the pole into the water vertically, the part of the pole that was seen above the water level is 0.25m

The first step is to calculate the length of the pole that is seen above the water level

= 4.80 × 0.25

= 1.20m

Therefore the depth of the water at that point can be calculated as follows

=4.80m - 1.20m

= 3.60m

Hence the depth of the water at that point is 3.60m

4 0

3 years ago

What is the shortest distance from the center of an inscribed circle to the sides of a triangle?

Thepotemich [5.8K]

I believe it would be the radius of the circle.

3 0

3 years ago

Read 2 more answers

Help me out and explain in how to do it I'll mark brainlist if you explain how do you solve this problem.

Klio2033 [76]

Is a y = Mx + b equations it’s B because c is our y and it look like it going up by 12 so every 1 Cube is 12 towers

8 0

3 years ago

Simplify completely. Leave your answer in exponential form:

stich3 [128]

Answer:

${2}^{3} \times {4}^{3} \times 9$

Step-by-step explanation:

Using the division rule when dealing with exponents

$\frac{b {}^{h} }{b {}^{j} } = b {}^{h - j}$

meaning that when we divide exponents that have the same base but different powers we can subtract the power of the bottom exponent from the top exponet.

so using that we are going to do 2, 4 and 9

$\frac{2 {}^{8} }{ {2}^{5} } = {2}^{8 - 5 = 3 \: \: \: \: \: 2 {}^{3} }$

$\frac{ {4}^{4} }{ {4}^{1} } = {4}^{4 - 1} \: \: \: {4}^{3}$

$\frac{9 {}^{9} }{ {9}^{8} } = {9}^{9 - 8} = 9 {}^{1}$

Combine all the terms and we get

${2}^{3} \times 4 {}^{3} \times {9}$

4 0

3 years ago