ST = 7.2
RT = 4.04
m∠S = 34°
Solution:
Given ΔRST is a right triangle.
RS = 6, ∠T = 56°
1.206 × 6 = ST
7.236 = ST
ST = 7.2
0.674 × 6 = RT
4.044 = RT
RT = 4.04
To find the measure of angle S.
Sum of the interior angles of the triangle = 180°
m∠R + m∠S + m∠T = 180°
90° + m∠S + 56° = 180°
m∠S + 146° = 180°
m∠S = 180° – 146°
m∠S = 34°
9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
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7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
Answer:
Do the parentheses first. then the operations. Then solve
Step-by-step explanation:
Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
11.25 minutes possibly
Step-by-step explanation:
1.forget the 17 liters for now
2. divide 45 & 4
3. you should get 11.25
