3 years ago

If sin θ=4/5 and 90°<θ<180°, what is cos θ?

Mathematics

1 answer:

34kurt3 years ago

7 0

Answer:

Cos ∅ = 3/5

BUT COSINE IS NEGATIVE IN THE SECOND QUADRANT.

Thus cos∅= -3/5

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Check the picture below. So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\$

$\bf -------------------------------\\\\
\begin{cases}
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\\\\\\
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