Answer:
Step-by-step explanation:
Hello,
hope this helps
Answer:
Cable attached height (Perpendicular) = 10√3 m
Step-by-step explanation:
Given:
Length of cable (Hypotenuse) = 20 m
Angle θ = 60°
Find:
Cable attached height (Perpendicular)
Computation:
Perpendicular/Hypotenuse = Sinθ
Perpendicular/20 = Sin 60
Perpendicular/20 = √3 / 2
Perpendicular = 10√3
Cable attached height (Perpendicular) = 10√3 m
Answer:
the answer is 306.25 feet and b is 8 sec
Step-by-step explanation:
Explanation
The height of the ball as a function of the time is given by the following formula:
A. Maximum height of the ball
To find the value of the maximum height, we maximum the function h(t) computing its first derivative and equalling the result to zero:
Solving the last equation for t, we get time t when the height is maximum:
So the maximum height is given by the value of h(t) when t = 2.5:
The maximum height is 196ft.
B. Time until the ball hits the ground
The ball will hit the ground when h(t) = 0. So we must find the value of t such that:
Solving this equation is equivalent to finding the roots of a second-order polynomial:
Where:
• a = -16,
,
• b = 80,
,
• c = 96.
The roots of this polynomial are given by the following formula:
s
Answer
A. The maximum height of the ball is 196 ft.
Answer:
I help u to find x
sln
<COE+ <AOE+ < DOA=180(because straight angle)
x+46+90=180
x+136=180
x=44
the angle ×=44
