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2 years ago

HELPPPPP FASTTTTTTTTTT PLEAAAAASE

Mathematics

1 answer:

emmainna [20.7K]2 years ago

6 0

Answer: Third option.

Step-by-step explanation:

To solve this exercise it is important to remember the following:

1) By definition, equivalent expression have the same value, but they look different.

2) The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

Then, given the following expression provided in the exercise:

$=(8.4x+2.9)+(-3.7x+5)$

You need to distribute the postive sign:

$8.4x+2.9-3.7x+5$

And finally, you must add the like terms:

$=8.4x-3.7x+2.9+5=4.7x+7.9$

As you can notice, the expression obtained matches with the expression shown in the third option.

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Brad knows the answer to 5 multiplied by 7 how does this help him solve the answer to 8 multiplied by 7?

dimaraw [331]

Answer:

Breaking up the multiplicand 8 into (5+3) allows us to apply the associative property of multiplication. See below.

Step-by-step explanation:

5*7 = 35. We want the product 8*7. Note that 8 = 5+3. Thus, 8*7=(5+3)(7) = 35 + 21, or 56.

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3 years ago

If f(x) = 6 - 5x, what is f(x)^-1? (check attachment)

SCORPION-xisa [38]

f(x) = 6-5x

y = 6-5x .... replace f(x) with y

x = 6-5y .... swap x and y; solve for y

x+5y = 6

5y = 6-x

y = (6-x)/5

$f^{-1}(x) = \frac{6-x}{5}$ ... replace y with the inverse function notation

<h3>Answer: Choice D.</h3>

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3 years ago

Write the product using exponents -3/7×3/7×3/7<br>

zlopas [31]

Answer:

$-(\frac{3}{7})^3$

Step-by-step explanation:

Since we see that 3/7 is multiplied by itself three times, we can use exponents as a shorter way to write this. The expontent tells us how many times the base number, 3/7, is multiplied by itself.

$-1 * (\frac{3}{7})^3$ = $-1 * \frac{3}{7} * \frac{3}{7} * \frac{3}{7}$

We then multiply by -1 to (3/7)^3 to get the exact answer.

$-(\frac{3}{7})^3$

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2 years ago

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

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2 years ago

PLEASE HELP!!! Which rule explains why these scalene triangles are similar

olchik [2.2K]

Answer: Ratio of Parts

<u>Step-by-step explanation:</u>

$\text{Ratio of sides:}\ \dfrac{ST}{WS+ST}=\dfrac{66}{6+66}=\dfrac{66}{72}=\dfrac{11}{12}\\\\\\\text{Ratio of bases:}\ \dfrac{TU}{TU+UV}=\dfrac{44}{44+4}=\dfrac{44}{48}=\dfrac{11}{12}\\\\$

The ratios are equal so the triangles are similar.

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2 years ago