Option A:
I and III only the answers.
Solution:
Let white vases be "w" and red vases be "r".
Cost of total flower = $336
Cost of each vase = $11
Total cost of the centerpieces
= Cost of (white vases + red vases) + Cost of flowers
= 11(w + r) + 336
= 11w + 11r + 336
Total cost of the centerpieces = 11w + 11r + 336 = 11(w + r) + 336
Therefore I and III only the answers.
Option A is the correct answer.
Answer:
option a
Step-by-step explanation:
Answer:
.7143
Step-by-step explanation:
there are 5 trouts so 5/7
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
Answer:
Yes.
Step-by-step explanation:
0.66 is 0.6600.