Answer:
1/2 and 3
Step-by-step explanation:
The quadratic formula is as given:
( -b±√(b^2-4ac) )/2a
To use it, plug in the a,b and c values.
ax^2+bx+c
In this case a is equal to 2, b is equal to -7, and c is equal to 3
plugging it into our formula gives us:
(-(-7)±√(-7^2-4*2*3) )/2*2
Which is equal to:
7±√(49-24) / 4
= 7±√25 / 4
=7±5 / 4
=2/4, 12/4= 1/2, 3
Answer:
The answer is A, 64%
Step-by-step explanation:
Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
Independent, the first roll and the second roll do not have any effect on each other
Answer:
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Step-by-step explanation:
What's the question
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