(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²
Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²
143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :
circumference of a circle = 2π.R = 2.π.12 = 75.41 m
Answer:
7.591 x 10^10
Step-by-step explanation:
You have to move the decimal point over until you have a number under 10 and also the number of times you had to move the decimal point at the end of the number over is your exponent for 10
P(4)= 1/8
This is because there are 8 equal parts and 4 is just one of those 8 parts.
The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.