You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)
Translating the line up 2 and right 9, so it goes through the given point, we get ...
... (x -9) +(y -2) = 0
or
... x + y = 11
Answer:
36.575
Step-by-step explanation:
you need to find line ab you can do
for the triangle and get the line you also need to get the squar root of it as it is still squared then devide by 2 to get the rades then times that by pi and there you go you have the area also sorry for spelling I love math not English
The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.
The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

The value of y is 23.
The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.

Thus, the value of x is 15 degrees.
The value of 12z is 45 degrees.

Thus, the required value of z is 3.75 degrees.
<h3>
Answer: 24 (choice C)</h3>
Assuming M is a midpoint of KW, this means that WM and KM are congruent
WM = KM
x+3 = 2(x-3) ... substitution
x+3 = 2x-6
2x-6 = x+3
2x-6-x = x+3-x .... subtract x from both sides
x-6 = 3
x-6+6 = 3+6 ... add 6 to both sides
x = 9
Use x = 9 to find the length of WM
WM = x+3 = 9+3 = 12
Which can be used to find the length of KM as well
KM = 2(x-3) = 2(9-3) = 2(6) = 12
both lengths are the same (12) as expected
This makes WK to be
WK = WM + KM
WK = 12 + 12
WK = 24