Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Hello!
The Answer Is 28.14
Because (42x33)/100=13.86
42.00-13.86=28.14
The correct answer for this question is that the unit rate is 5:1. We
can work this out by simplifying down the 2 commercials to every 10
songs ration, so that 10:2 becomes 5:1. We can work this out by halving
the original ratio to simplify it.