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Masja [62]
3 years ago
14

What is the solution to −4x+5y=−12 x−6y=22

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

The solution to the system is S= (-2, -4).

Step-by-step explanation:

Given the system

−4x+5y=−12

x−6y=22

The first step is to solve x from the first equation for example, and substitute the expression in the second equation.

1) -4x + 5 y = -12 ⇒ -4x = -12 - 5y ⇒ x = (-12 - 5y)/-4 ⇒ x = 3 + (5/4)y

2) x - 6y = 22 ⇒ (3 + (5/4)y) - 6y = 22 ⇒ 3 + (5/4)y - 6y = 22

⇒ 3 - (19/4)y = 22 ⇒ (-19/4)y = 22- 3 ⇒ y = 19/(-19/4) ⇒ y =-4.

Finally, with the value obtained for "y", you have to return to the original equations and replace it to obtain the "x" value.

-4x + 5y = -12 ⇒ -4x + 5(-4) = -12 ⇒ -4x - 20 = -12 ⇒ -4x = -12 + 20

⇒ -4x = 8 ⇒ x = 8/-4 ⇒ x = -2.

Summarizing, the solution to this system is S = (-2, -4).

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professor190 [17]

Answer:

4/10

Step-by-step explanation:

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3 years ago
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A person in a casino decides to play 3 games of blackjack. let w denote a win and l denote a loss. define the event a as "the pe
Ann [662]

Answer: The answer is {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.



Step-by-step explanation: Given that a person in the casino is going to play 3 games of blackjack. Here, 'w' denotes a win and 'l' denotes a loss.  

Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

(i) win in 1st game     loss in 2nd game       loss in 3rd game

(ii) win in 1st game     win in 2nd game        loss in 3rd game

(iii) win in 1st game     loss in 2nd game       win in 3rd game

(iv) win in 1st game     win in 2nd game        win in 3rd game

(v) loss in 1st game     loss in 2nd game       win in 3rd game

(vi) loss in 1st game     win in 2nd game        loss in 3rd game

(vii) loss in 1st game     win in 2nd game       win in 3rd game

Thus, the outcomes of the event A are (w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l) and (l, w, w).

Thus, A = {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.


5 0
2 years ago
13. Solve the equation: y = 4x + ax + 6 for a.
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Answer:

a= (y-4x-6)/X

Step-by-step explanation:

Make ax the subject of the formulae

-ax=4x+6-y

Multiply both sides by minus (-)

ax= y-4x-6

Divide both sides by x

a= (y-4x-6)/x

4 0
3 years ago
E bisects DF , DE = 5y, and EF = 13y-8. Find DE, EF, and DF
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It bisects so DE=EF

DE=5y
EF=13y-8

so
5y=13y-8
minus 13y both sides
-8y=-8
divide both sides by -8
y=1

DE=5y=5(1)=5

DE=EF=5

DF=DE+EF=5+5=10

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7 0
2 years ago
ABCD is a trapezium AD and BC are parallel
Orlov [11]

Part (a)

<h3>Answer:  12.1</h3>

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

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x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

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Make sure your calculator is in degree mode.

===================================================

Part (b)

<h3>Answer:  15.1</h3>

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\

d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\

Segment CD is roughly 15.1 cm long.

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