Answer: -8 and -4
This is something you do through trial and error. Making a list or a table like shown below might help.
D.) y= 0.3x
This is because slope is change in y over change in x, so we get 3/10 which is equivalent to 0.3
Answer:
The answer is below
Step-by-step explanation:
The diameter of a tire is 2.5 ft. a. Find the circumference of the tire. b. About how many times will the tire have to rotate to travel 1 mile?
Solution:
a) The circumference of a circle is the perimeter of the circle. The circumference of the circle is the distance around a circle, that is the arc length of the circle. The circumference of a circle is given by:
Circumference = 2π × radius; but diameter = 2 × radius. Hence:
Circumference = π * diameter.
Given that diameter of the tire = 2.5 ft:
Circumference of the tire = π * diameter = 2.5 * π = 7.85 ft
b) since the circumference of the tire is 7.85 ft, it means that 1 revolution of the tire covers a distance of 7.85 ft.
1 mile = 5280 ft
The number of rotation required to cover 1 mile (5280 ft) is:
number of rotation =
To evaluate the expression all you have to do is substitute the value for the variable.
3 + y + 6, y = 5
3 + 5 + 6
8 + 6
14.
The solution is 14.
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)