Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
Answer:
2i: 169.71
2ii: 0.17L
3a: 4×10⁻⁵
3b: 110011
Step-by-step explanation:
2i. The surface of the top and bottom of the tin is two times (top and bottom) π·r² = 2·π·3² = 18π cm².
The circumference of the circle is 2·π·r = 6π cm².
The area of the material connecting top and bottom is a rectangle of the tin height times the circumference: 6·6π = 36π cm².
This gives a total of 18π + 36π = 54π cm².
With π approximated by 22/7 the total surface area is 54*22/7 ≈ 169.71.
Notice how the calculation is simple by waiting until the very last moment to substitute π.
2ii. The volume is the area π·r² of the circle times the height of the tin: 9π*6 = 54π cm³ ≈ 169.71 cm³.
Since 1L = 1000 cm³ the volume is 0.16971 litres, which should be rounded to 0.17 L.
3a: If we rewrite P as 36 x 10⁻⁴ and realize that 36/2.25 = 16, then the fraction can be written as
16 x 10⁻⁴⁻⁶ = 16 x 10⁻¹⁰.
The square root of that is taking it to the power of 1/2, so (16x10⁻¹⁰)^0.5 = 4x10⁻⁵ = 0.00004
3b: 1111 1111 is 255 in decimal. 101 is 5 in decimal. 255/5 is 51 in decimal. 51 in binary is 110011.
Answer:
I am pretty sure that $15.50 is the answer
Answer:2\6 or 4\12 etc.
Step-by-step explanation: