All categories

3 years ago

Write an equation that represents the following problem.

1 answer:

5 0

35 + 0.05m = 50 + 0.01m <== ur equation
0.05m - 0.01m = 50 - 35
0.04m = 15
m = 15/0.04
m = 375.....u need to send 375 text messages for the plans to be equal

You might be interested in

A football team took possession of the ball on the 50 yard line. They lost 5 yards on the first down, and lost another 6 yards o

trapecia [35]

Answer: The answer should be 39 yard line

Step-by-step explanation: If you start at the 50 and remove 11 yards you will have 39 yards left

5 0

3 years ago

#1: Write the equation of the graphed line. NO SPACES, ALL LOWERCASE. <br> Please help

ivanzaharov [21]

Answer:

Equation of graphed line is $\mathbf{y=\frac{2}{3}x-3}$

Step-by-step explanation:

We need to write the equation of the graphed line.

The equation will be in slope intercept form $y=mx+b$ where m is slope and b is y-intercept

We need to find slope and y-intercept.

Finding slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We will use points (0,-3) and (3,2)

Looking at the graph, we get $x_1=0, y_1=-3, x_2=3, y_2=-1$

Putting values in graph and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-1-(-3)}{3-0} \\Slope=\frac{-1+3}{3} \\Slope=\frac{2}{3}$

So, we get slope $\mathbf{\frac{2}{3} }$

Finding y-intercept

y-intercept can be found when x is zero.

So, looking at graph, when x =0, y=-3

So, y-intercept is -3

Equation of Line

So, equation of line having slope $\mathbf{\frac{2}{3} }$ and y-intercept b = -3

$y=mx+b\\y=\frac{2}{3}x-3$

So, Equation of graphed line is $\mathbf{y=\frac{2}{3}x-3}$

8 0

3 years ago

A climber on Mt Everest is 6000 meters from the start of his trail and at elevation 8000 meters above sea level. At x meters fro

sergeinik [125]

Answer:

h'(x) = 0.6 and Δx = 1 and 2

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Explanation below:

Step-by-step explanation:

Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.

We know that the function for elevation is given by h(x) where x is the number of meters from the start.

Therefore, h(6000) = 8000.

We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)

We need to use the derivative at a point to estimate values of the function at nearby points

We're going to use h'(x)= 0.6. Δx= 1

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

Therefore h (6001) = 8,000.6

Now for h'(x)= 0.6. Δx= 1

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Therefore h(6002) = 8001.2

6 0

3 years ago

Alexandra purchases two donuts and three cookies at the donut shop and it's charged $3.30. Brianna purchases five donuts and two

Amiraneli [1.4K]

Given: