Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point[-6,2]

1 answer:

5 0

I think the answer is: y-2=1(x-(-6))

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Komok [63]

That would be a / 3b^2

(re call that 1 /a^-1 = a)

6 0

3 years ago

Rasek [7]

Answer:

60% of 500 is 300 and 40% of 500 is 200. 300-200=100

Step-by-step explanation:

4 0

2 years ago

nataly862011 [7]

Answer:

1545.66 rad/h

Step-by-step explanation:

We need to find the angular velocity in rad/hour when wind is moving with a speed of 4.1 rpm.

We know that,

1 revolution = 2π rad

1 hour = 60 minute

So,

$4.1\ rmm = 4.1\times \dfrac{2\pi }{(\dfrac{1}{60})}\ rad/h\\\\=1545.66\ rad/h$

So, the required angular velocity is 1545.66 rad/h.

6 0

3 years ago

agasfer [191]

2 times x -4=12
2x-4=12
Let x= 8
(2.8)-4=12
16-4= 12

So the answer is 8

8 0

2 years ago

Trava [24]

Answer:

Step-by-step explanation:

4 0

2 years ago