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Answer:
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Forecast of rain.
Event B: Raining.
In recent years, it has rained only 5 days each year.
A year has 365 days. So
When it actually rains, the weatherman correctly forecasts rain 90% of the time.
This means that
Probability of forecast of rain:
90% of 0.0137(forecast and rains)
10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)
What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
Answer: The simplified form of above expression is
Step-by-step explanation:
Since we have given that
We need to solve the above expression to get the simplified answer:
1) Take the L.C.M. of 10 and 3.
L.C.M. of 10 and 3 = 30
2) Make the denominator 30 for each of the fraction .
3) Take the difference between them:
Hence, the simplified form of above expression is