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suter [353]
3 years ago
6

Solve for c 8/3c -2= 2/3c-12

Mathematics
2 answers:
Tom [10]3 years ago
5 0

\text{Solve for c:}\\\\\frac{8}{3c-2}=\frac{2}{3c-12}\\\\\text{Cross multiply}\\\\8(3c-12)=2(3c-2)\\\\24c-96=6c-4\\\\\text{Subtract 6c from both sides}\\\\18c-96=-4\\\\\text{Add 96 to both sides}\\\\18c=92\\\\\text{Divide both sides by 18}\\\\c=\frac{92}{18}\\\\\text{Simplify}\\\\\boxed{c=\frac{46}{9}}

Anna [14]3 years ago
4 0

Answer: C = -5

Step-by-step explanation:

You have to add two on both sides and the remove 2/3 on both sides. Hope this helps

<!> Brainliest is appreciated! <!>

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Answer:

The dimension of box=2ft\times 2ft\times 1ft

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box=lbh=x^2h

4=x^2h

h=\frac{4}{x^2}

Now, surface area of box,A=x^2+4xh

A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}

\frac{dA}{dx}=2x-\frac{16}{x^2}

\frac{dA}{dx}=0

2x-\frac{16}{x^2}=0

2x=\frac{16}{x^2}

x^3=8

x=2

\frac{d^2A}{dx^2}=2+\frac{32}{x^3}

Substitute x=2

\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h=\frac{4}{2^2}=1 ft

Hence, the dimension of box=2ft\times 2ft\times 1ft

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2 years ago
Stephen, Gavin and Jim share some sweets in the ratio 4:1:2. Stephen gets 30 more sweets than Jim. How many sweets are there alt
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Answer:

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Step-by-step explanation:

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Daniel and Edwin went to lunch. Daniel’s meal cost $20 and Edwin’s meal cost $18.50. They each left an 18% tip on the price of t
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Answer:

$45.43

Step-by-step explanation:

20 × 0.18 = 3.60

18.50 × 0.18 = 3.33

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