Solve for c 8/3c -2= 2/3c-12

2 answers:

5 0

$\text{Solve for c:}\\\\\frac{8}{3c-2}=\frac{2}{3c-12}\\\\\text{Cross multiply}\\\\8(3c-12)=2(3c-2)\\\\24c-96=6c-4\\\\\text{Subtract 6c from both sides}\\\\18c-96=-4\\\\\text{Add 96 to both sides}\\\\18c=92\\\\\text{Divide both sides by 18}\\\\c=\frac{92}{18}\\\\\text{Simplify}\\\\\boxed{c=\frac{46}{9}}$

Anna [14]2 years ago

4 0

Answer: C = -5

Step-by-step explanation:

You have to add two on both sides and the remove 2/3 on both sides. Hope this helps

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