Answer:
y = 4x + 1
Step-by-step explanation:
Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope
Standard form of an equation is y = mx + b
Compare;
mx = 4x
m = 4
Since the slope of the given equation is 4, the required equation must also have a slope of 4
Since we are not given an option, we can assume any equation with a slope of 4
y = 4x + 1 will be parallel to the given equation since they both have the same slope
<em>Note that the equation can be different so far they have the slope of 4</em>
Answer:
3rd option: x= 40
Step-by-step explanation:
4x° +20°= 180° (adj. ∠s on a str. line)
<em>Bringing</em><em> </em><em>constants</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>:</em>
4x°= 180° -20°
<em>Simplify</em><em>:</em>
4x°= 160°
<em>Divide</em><em> </em><em>by</em><em> </em><em>4</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
x°= 40°
Thus, x=40.
Answer:
Step-by-step explanation:
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Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.