Answer:
x^2 – 3xy + 2y^2
Step-by-step explanation:
Factor the following:
x^2 - 3 x y + 2 y^2
Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.
The factors of 2 that sum to -3 are -1 and -2. So, x^2 - 3 x y + 2 y^2 = (x - 1 y) (x - 2 y):
Answer: (x - y) (x - 2 y)
When x is equal to -1:
f(-1)=6(-1)-3
=-7-3
=-10
y=-10
When x is equal to 0:
f(0)=6(0)-3
=0-3
=-3
y=-3
When x is equal to 1:
f(1)=6(1)-3
=6-3
=3
y=3
When x is equal to 2:
f(2)=6(2)-3
=12-3
=9
y=9
The function’s value when x = −1 will be C. g(−1) = 1.
<h3>How to calculate the value of the function?</h3>
It should be noted that that a function is simply used to show the relationship that exists between the variables.
There's a 2-column table with 5 rows. The first column is labeled g of x with entries negative 3, negative 2, 0, 2, 3. The second column is labeled f of x with entries.
The. function is x³ + 6x² + 12x + 8.
= x³ + 6x² + 12x + 8.
= (-1)³ + 6(-1)² + 12(-1) + 8
= -1 + 6 - 12 + 8
= 1
Therefore, the correct option is C.
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70a + 55b = 905
a + b = 14
55a + 55b = 770
(70a-55a) + (55b-55b) = 905 - 770
15a = 135
a = 9
a + b = 14
9 + b = 14
b = 5
