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saw5 [17]
3 years ago
5

What is the range of the function? A. (-1,3,5) B. (2,6,8,3,5) C. {3} D. (2,6,8)

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

I think the answer is D. (2,6,8) because if the ones on the right are y - coordinates in the Function then it should be correct. If not sorry

(Range is y - coordinate)

(Domain is x - coordinate)

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Answer:

30

Step-by-step explanation:

the value of x, bring the variable to the left side and bring all the remaining values to the right side

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What does "opposite semi-planes of segment" mean?
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opposite half-planes – the two half-planes that are separated by a particular line of the plane. If points Y and Z are in opposite half-planes, the segment joining them must intersect the edge.

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3 years ago
Which of the following represents "five times the sum of a number and fifteen is fifty"?
Kisachek [45]
Yes, the correct answer is A because you're multiplying 5 by the expression (N+15)
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Jimmy takes a loan of 10,000$ at 12% per year as rate of interest . Find the amount, he will be required to pay after 1 year to
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Step-by-step explanation:

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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