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tino4ka555 [31]
4 years ago
6

Ralph is purchasing a new gaming system for $300.00. He is trying to decide whether he wants to use cash or his credit card to p

ay. He has $600.00 available in his checking account. Which of the following is not an argument that justifies Ralph's use of his cash to purchase the gaming system? a. Using cash can help Ralph improve his credit score. b. Using cash may limit overspending or impulse buying. c. Cash doesn't come with any potential "over limit" or "late payment" fees. d. Cash will be the easiest method of payment with very few security measures involved.
Mathematics
2 answers:
ra1l [238]4 years ago
6 0

Using cash can help Ralph improve his credit score is just untrue in so many ways.


The answer is choice A because the statement does not justify Ralph's use of cash.

timurjin [86]4 years ago
6 0

Ralph is purchasing a new gaming system for $300.00. He is trying to decide whether he wants to use cash or his credit card to pay. He has $600.00 available in his checking account.

The following statement is not an argument that justifies Ralph's use of his cash to purchase the gaming system-

Using cash can help Ralph improve his credit score.

An argument can be defined as a reason or set of reasons given with the aim of persuading others that an action or idea is right or wrong.

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Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Number of people living in Georgia = 10,100,000

Number of people living in per square mile = 170

So, we need to find the area of the state :

So, Area of the state is given by

\frac{\text{Total Population}}{\text{ Number of people per square mile }}\\\\=\frac{10100000}{170}\\\\=59411.76\\\\=59400(\text{ nearest hundred }mi^2)

Hence, Option 'D' is correct.

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\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
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(b)
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VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

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we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
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c=hypotenuse\\
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\\\\\\
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recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
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% tangent
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\\\\\\
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therefore, let's just plug that on the remaining ones,

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