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eduard
3 years ago
13

What are the zeros of the function y=2x^2 +7x+3

Mathematics
1 answer:
enyata [817]3 years ago
5 0
The zeros are (-3,0) and (-0.5,0)
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A number has the same digit in its hundreds place and its hundredths place.
aksik [14]

Answer:

it is 10 times greater

Step-by-step explanation:

hope this helps :)

7 0
3 years ago
David made a scale drawing of a mural he is going to paint. He used a scale of 1 cm=4ft. If the actual mural will be 16 feet lon
VikaD [51]

Answer:

4 cm

Step-by-step explanation:

we know that

The scale drawing is

\frac{1}{4}\ \frac{cm}{ft}

That means ----> 1 cm in the drawing represent 4 ft in the mural

so

To find out the dimensions in the drawing, multiply the actual dimension by the scale drawing factor

so

(16\ ft)(\frac{1}{4}\ \frac{cm}{ft})=4\ cm

3 0
3 years ago
If h(x) is the inverse of f(x). what is the value of h(f(x))?
attashe74 [19]

Option C is correct

The value of h(f(x)) is, x

Inverse function:

An inverse function that undergoes the other function.

For example: if f(x) is the inverse of g(x) then;

for every x.

As per the statement:

If h(x) is the inverse of f(x).

by definition of inverse:

Therefore,  the value of h(f(x)) is, x

6 0
3 years ago
Read 2 more answers
Describe how you would get to point (4,-3)
m_a_m_a [10]
The answer is c, right 4 down 3
8 0
3 years ago
The two pyramids are similar. Find the volume of the smaller pyramid. Round your answer to the nearest hundredth.
mihalych1998 [28]

Answer:

A) 5.12mm³

Step-by-step explanation:

Step 1

Find the volume of the bigger pyramid

This is a triangular based pyramid.

The formula to use is given as Volume of Pyramid =

1/3 × Area of the triangle × Height

Area of the triangle = 1/2 × 3 mm × 4mm = 6mm²

Volume of the large pyramid = 1/3 × 6mm² × 5mm

= 10mm³

We are given the length of the small pyramid as 4mm

We would be using was is known as scale factor to find the volume of the small pyramid

The scale factor k = (Height of the small pyramid)³/ (Height of the Large pyramid)³

k = 4³/5³

k = Volume of small pyramid/ Volume of large pyramid

Volume of small pyramid = X

Volume of large pyramid = 10mm³

Hence,

4³/5³ = X/10

Cross Multiply

= 4³ × 10 = 5³ × X

X = (4³ × 10)/ 5³

X = 5.12mm³

5 0
3 years ago
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