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maw [93]
3 years ago
8

What is the answer to this?​

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

-3x+4y=0 .

Step-by-step explanation:

the line passed through the point (-3,4) and thoch through the origin(0,0)

the the equation become -3x+4y=0.

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Find the y-intercept of the following equation. Simplify your answer.<br><br> y = 10x + 6
hram777 [196]

Answer:  6

Step-by-step explanation:

y = mx + b, where b is the y-intercept, in this case, y-intercept is 6.

3 0
3 years ago
Solve: 2.5k+47.4=81.9
belka [17]

Answer:

k=13.8

Step-by-step explanation:

Given function:

  • 2.5k+47.4=81.9
  • to find k..

<u><em>Subtract final and middle value:</em></u>

  • 81.9-47.4= 34.5

<em><u>Divide by 2.5:</u></em>

  • 34.5*2.5=13.8

Therefore, k=13.8..

8 0
3 years ago
A group of 196 students needs to be seated in a square formation for a yearbook photo. How many students should be in each row?
givi [52]

Answer:

There should be a number of 14 students in each row

Step-by-step explanation:

Find the factors of 196 then find the Greatest factor pairs which give you the numbers of 14 and 14. Now you have your answer of 14 rows and 14 columns.

6 0
3 years ago
How do you find the radius of a cylinder?
zmey [24]

Answer:

√(V / π × h), where V is the volume of the cylinder, h is the height, and π(Pi) is a mathematical constant with an approximate value of 3.14

7 0
3 years ago
Read 2 more answers
At Least One Defective iPhone It has been reported that 20% of iPhones manufactured by Foxconn for a product launch did not meet
bija089 [108]
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
7 0
3 years ago
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