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Delicious77 [7]
3 years ago
15

Solve using algebreic methods y=x^2+5x, y=7-x

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

x = 1 and x = -7

Step-by-step explanation:

Given that,

y=x^2+5x  ...(1)

and

y = 7 -x ....(2)

Put the value of y from equation (2) in (1)

7-x=x^2+5x\\\\x^2+5x-7+x=0\\\\x^2+6x-7=0\\\\x^2+7x-x-7=0\\\\x(x+7)-1(x+7)=0\\\\(x-1)(x+7)=0

So,

x = 1 and x = -7

Hence, the solution of the given equations is x = 1 and x = -7

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4 0
3 years ago
I need help with #11 and #12 how do I do this?
USPshnik [31]

Answer:

  11. x = 6; y = 6.5

  12. x = 2; y = 4

Step-by-step explanation:

In each figure, the hash marks on the lines indicate the parallel lines (marked with red arrows) are equally-spaced. That means the two expressions involving x are equal to each other, and the two expressions involving y are equal to each other.

__

11. 2x +1 = x +7

  x = 6 . . . . . . . subtract (x+1) from both sides

and

  3y -8 = y +5

  2y = 13 . . . . add (8-y) to both sides

  y = 6.5 . . . . divide by the coefficient of y

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12. x +3 = 3/2x +2

  1 = 1/2x . . . . . subtract (x+2)

  2 = x . . . . . . . multiply by 2

and

  2y -1 = 3y -5

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8 0
3 years ago
Read 2 more answers
Explain the difference between four times the sum of X and Y and the sum of four times X and Y
tester [92]

Answer:

Condition 1:

four times the sum of X and Y = 4(X + Y)

Condition 2:

the sum of four times X and Y=  4X + Y

  • Difference:

        In condition 1, both the variables are first added and then multiplied by        four. This can be simplified as:

                   4X +4Y

I condition 2, only the variable X is multiplied with 4 and then added to Y.

  • Conclusion:

         With positive integers, condition 1 will always give a greater value.

         With negative integers, condition 2 will have greater value.

I hope it will help you!

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3 years ago
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Write the product in simplest form: 3w^4 * (-5w^2)
Grace [21]

3w^{4} (-5w^{2} ) = -15w^{6}

I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.

When you multiply the exponent:

(x²)³ = x^{6}

(3x^{4} )^{2} = 9x^{8}

When you add the exponents:

(x²)(x³) = x^{5}

(x²)(x²) = x^{4}

(x^{4} )(x^{3} ) = x^{7}

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