Answer:Serkan teacher regularly buys 75 TL of gasoline in his car every week.
At the end of the 13th week, how much is the total gasoline expenditure made by the serkan teacher?
A)390 B)420 C)900 D)975
Explanation:
Answer:
The abyssal zone or abyssopelagic zone is a layer of the pelagic zone of the ocean. "Abyss" ... This region also contains a much higher concentration of nutrient salts, like ... Many animals also move very slowly to conserve energy. Their reproduction rates are also very slow, to decrease competition and conserve energy.
Explanation:
Rather than relying on producers to form the base of the food pyramid, organisms living in the abyssal zone must feed on the dead organic detritus that falls from oceanic layers above. ... For example, many of these organisms convert hydrogen sulfide to sulfate to produce chemical energy.
Answer:
18.1 g
Explanation:
You know that the atomic weight of phosphorus is equal to
30.794 u
, where
u
represent the unified atomic mass unit.
The unified atomic mass unit is equivalent to
1 g/mol
, but let's take the long road and prove that identity.
Now, the unified atomic mass unit is defined as
1
12
th
of the mass of a single unbound carbon-12 atom in its ground state and is equivalent to
1 u
=
1.660539
⋅
10
−
24
g
This means that the mass of one phosphorus atom will be
30.974
u
⋅
1.660539
⋅
10
−
24
g
1
u
=
5.14335
⋅
10
−
23
g
You know that one mole of any element contains exactly
6.022
⋅
10
23
atoms of that element - this is known as Avogadro's number.
Well, if you know the mass of one phosphorus atom, you can use Avogadro's nubmer to determine what the mass of one mole of phosphorus atoms
5.14335
⋅
10
−
23
g
atom
⋅
6.022
⋅
10
23
atoms
1 mole
=
30.974 g/mol
Finally, if one mole of phosphorus atoms has a mass of
30.974 g
, then
0.585
moles will have a mass of
0.585
moles
⋅
30.974 g
1
mole
=
18.1 g
From: https://socratic.org/questions/the-atomic-weight-of-phosphorus-is-30-974-u-what-is-the-mass-of-a-phosphorus-sam
2N2 + 3O2 ---> 2NO + 2NO2
You should do it based on moles and not grams.
1.14 g O = 0.071 moles O
1 g N = 0.071 moles N
So in NO2 you need 2 moles O for each mole of N
1 g N = 0.071 moles, so you need 0.071 x 2 moles of O = 0.0.142 moles O
0.142 moles O x 16 g/mol = 2.27 grams of O. So, you are actually correct because your answer is 2.28 grams. I just prefer to work it out in moles so it makes perfect chemical sense.
