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Lemur [1.5K]
3 years ago
15

Which of the following is an accurate mathematical expression of Dalton's law? Assume the variable ‘P' stands for pressure.

Chemistry
1 answer:
GaryK [48]3 years ago
8 0
Dalton's law of partial pressures states that the total pressure of a mixture of gases is the sum of the partial pressures of its components:
\text {P}_{\text{Total}} = \text P_{\text {gas 1}} + \text P_{\text {gas 2}} + \text P_{\text {gas 3}} ...P
​Total
​​ =P
​gas 1
​​ +P
​gas 2
​​ +P
​gas 3
​​ ...
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Answer:

5.2 millimeters

Explanation:

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3 years ago
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A chemist weighed out 19.9 g of aluminum. Calculate the number of moles of aluminum she weighed out.
vodomira [7]
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3 0
3 years ago
Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

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