◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer:
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The <u><em>Power of a Power Property</em></u>
, states that :To find a power of a power, multiply the exponents
so
In this problem we have
![9^{\frac{1}{3}} =\sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B9%7D)
Remember that
![\sqrt[3]{9}=9^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Raise to the third power
![[9^{\frac{1}{3}}]^3](https://tex.z-dn.net/?f=%5B9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5D%5E3)
Applying the power of power property
therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Answer:
29/28
Step-by-step explanation:
The 12 inch pizza is a better deal because the 12 inch pizza sells for $1 per 9.04 in and the 8 inch sells for $1 per 7.17.The 12 inch pizza sells a greater amount per dollar.Hope that helps
