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Mnenie [13.5K]
4 years ago
8

Sandy has 8 markers. Alex has 6 fewer markers than sandy. Jill has 2 markers. How many markers do they have in all? Show your wo

rk. Then explain how you found the answer.
Mathematics
2 answers:
givi [52]4 years ago
4 0
If sandy has 8 and alex has 6 fewer than alex has 2. Since Jill has 2 then you add 8 plus 2 plus 2 which equals 12. So there is 12 all together
expeople1 [14]4 years ago
3 0

so alex would have 2 markers plus jills 2 markers plus 8 markers is 12 markers all together, feel free to comment if you don't understand fully, and i will try to better my explanation

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Answer:

1. x_1=2\sqrt{2}\\x_2=-2\sqrt{2}\\x_3=i2\sqrt{2}\\x_4=-i2\sqrt{2}

2. A=(2\sqrt{2},0) and B=(-2\sqrt{2},0)

Step-by-step explanation:

We have the expression x^4-64=0 to find the solutions we have to clear x. Then,

x^4-64=0 Add 64 in both sides of the equation.

x^4-64+64=64\\x^4=64

Now we have to re-write the equation:

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u^2=64

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\sqrt{u^2}=\sqrt{64}\\u=8 , u=-8

Now substitute back u=x^2

1. x^2=8

2. x^2=-8

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1. x=+\sqrt{8}=\sqrt{2^3}=\sqrt{2^2}.\sqrt{2}\\x=2\sqrt{2}\\or\\x=-\sqrt{8}\\x=-2\sqrt{2}

2. x=+\sqrt{-8}=\sqrt{(-1).8} =\sqrt{-1}\sqrt{8} \\x=i\sqrt{8}\\x=i.2\sqrt{2} \\or\\x=-\sqrt{-8}\\x=-i.2\sqrt{2}

Then the solutions for x^4-64=0 are:

x_1=2\sqrt{2}\\x_2=-2\sqrt{2}\\x_3=i2\sqrt{2}\\x_4=-i2\sqrt{2}

To find the x intercepts of the graph y=x^4-64 we have to replace with y=0.

This means: x^4-64=0

We already found the solutions for the expression, but we have to consider only the real solutions.

x_1=2\sqrt{2}\\x_2=-2\sqrt{2}

Because in a graph we can't have imaginary solutions.

Then the x intercepts of the graph are:

A=(2\sqrt{2},0) and B=(-2\sqrt{2},0)

The graph of the function is:

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