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igor_vitrenko [27]
3 years ago
8

Identify an equation in point-slope form for the line perpendicular to y = 3x + 5

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

perp.: -1/3

y + 1 = -1/3(x - 4)

y + 3/3 = -1/3x + 4/3

y = -1/3x + 1/3

Step-by-step explanation:

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The coordinates of the vertices of A ABC are A(1, 1), B(5, 1), and C(5, 3). The
Mariana [72]

Answer: ABC is congruent to A’B’C because yo can nap ABC to A’B’C using a rotation of 180 degrees about the origin, which is A rigid motion

6 0
2 years ago
Noah started with a number, x. He took the difference of four times the number and three and cubed the result. Write the express
Oksi-84 [34.3K]

Answer:

The expression representing Noah’s new number is (4x-3)^3.

Step-by-step explanation:

Noah started with a number, x.

Four times the number x is 4x

The difference of four times the number and three is 4x - 3

The difference of four times the number and three cubed is (4x-3)^3

Thus, the expression representing Noah’s new number is (4x-3)^3.

4 0
3 years ago
Express 4 percent as decimal
malfutka [58]

Answer:

0.04

Step-by-step explanation:

move the decimal over to te left 2 places.

7 0
3 years ago
Which is the graph of g(x)=10/x
Elan Coil [88]

Answer:

y=0

Step-by-step explanation:

Find where the expression  

10

x

is undefined.

x

=

0

Consider the rational function  

R

(

x

)

=

a

x

n

b

x

m

where  

n

is the degree of the numerator and  

m

is the degree of the denominator.

1. If  

n

<

m

, then the x-axis,  

y

=

0

, is the horizontal asymptote.

2. If  

n

=

m

, then the horizontal asymptote is the line  

y

=

a

b

.

3. If  

n

>

m

, then there is no horizontal asymptote (there is an oblique asymptote).

Find  

n

and  

m

.

n

=

0

m

=

1

Since  

n

<

m

, the x-axis,  

y

=

0

, is the horizontal asymptote.

y

=

0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:  

x

=

0

Horizontal Asymptotes:  

y

=

0

No Oblique Asymptotes

image of graph

3 0
3 years ago
What are the solution(s) to the quadratic equation 40 − x2 = 0? x = ±2 x = ±4 x = ±2 x = ±4
Alexandra [31]

Answer: x=\±2\sqrt{10}

Step-by-step explanation:

To find the solutions of the quadratic equation given in the problem, you can apply the proccedure shown below:

- Subtract 40 from both sides of the equation.

- Multiply both sides of the equation by -1

- Apply square root to both sides of the equation.

Therefore, by applyin the steps above, you obtain:

40-x^2-40=0-40\\-x^2=-40\\(-1)(-x^2)=(-40)(-1)\\\\x^2=40\\\\\sqrt{x^2}=\±\sqrt{40}\\\\x=\±2\sqrt{10}

8 0
3 years ago
Read 2 more answers
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