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igor_vitrenko [27]
3 years ago
8

Identify an equation in point-slope form for the line perpendicular to y = 3x + 5

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

perp.: -1/3

y + 1 = -1/3(x - 4)

y + 3/3 = -1/3x + 4/3

y = -1/3x + 1/3

Step-by-step explanation:

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Answer:

y = 2(3)^{x}

Step-by-step explanation:

For the exponential function in the form

y = ab^{x}

Use ordered pairs from the table to find a and b

Using (0, 2 ), then

2 = ab^{0} ( b^{0} = 1 ) , thus

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y = 2(3)^{x}

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3 years ago
Solve the slope for the table.
Nikitich [7]

Answer:

The slope is 0

Step-by-step explanation:

All y-values are equal to 5 meaning the graph is a straight horizontal line. Slope is the rate at which a graph increases or decreases. Seeing as this graph doesn't do so, the slope is 0.

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What does y is two less than x stand for
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Match each scenario involving projectile motion with the equation that describes the height of the object at time t. Tiles h = -
olga55 [171]

Answer:

  1. h = -16t^2 + 73t + 5
  2. h = -16t^2 + 5
  3. h = -4.9t^2 + 73t + 1.5
  4. h = -4.9t^2 + 1.5

Step-by-step explanation:

The general equation we use for ballistic motion is ...

  h(t)=\frac{1}{2}gt^2+v_0t+h_0

where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.

The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.

_____

Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)

A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)

Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)

Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)

_____

<em>Additional comment on these scenarios</em>

The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for <em>vertical</em> motion, so we must assume the launches are <em>straight up</em> (or that the up-directed component of motion is 73 units/second).

4 0
3 years ago
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