Answer:
E(29/4,3)
Step-by-step explanation:
Given that,
Segment CD has point E located on it such that CE:ED = 3:5
The coordinates of C and D are (5, -6) and (11,18) respectively.
We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :

So, the coordinates of E are (29/4,3).
The greatest place value is the tens spot which 2 is in the tens spot so we need to round up since 5 is next to the 2. The answer would be 30
The answer is c = 0
Explanation, see the picture
1,3,5 because they are all negatives less than -3
Ok there is 7 students in total… the ratio of boys to girls is 5 to 2, so 5 divided by 7 is 0.714%