Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
Answer:
0
Step-by-step explanation:
if all the liquid is exactly 4 liters as from the beaker to a empty container
then it can hold zero more
On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.
- 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
- 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Thus making 40 and 80 the answers. I hope this helps!
The amount of salt in the tank changes with rate according to
which is a linear ODE in 
. Multiplying both sides by 
gives
so that the left side condenses into the derivative of a product,
Integrate both sides and solve for to get
Given that 
, we find
and we get the particular solution
B) y=58 you follow the instructions
