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Andru [333]
3 years ago
8

-6 ÷ -2 (-1 - 3)2 x -1

Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0

Answer:

-24

Step-by-step explanation:

-6 ÷ -2(-1 - 3)2 x 1

PEMDAS (parenthesis, exponents, multiplication/division left to right, addition/subtraction left to right)

Parenthesis

-6 ÷ -2(-4)2 x 1

Left to right

3(-4)2 x 1

-12 x 2 x 1

-24 x 1

-24

I Hope That This Helps! :)

nexus9112 [7]3 years ago
4 0

Answer:

=−16.309691bd3i2vy−16

Step-by-step explanation:

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As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0
3 years ago
If all the liquid from the beakers is poured into one empty container that can hold exactly 4 liters, how much more liquid can t
Luba_88 [7]

Answer:

0

Step-by-step explanation:

if all the liquid is exactly 4 liters as from the beaker to a empty container

then it can hold zero more

7 0
3 years ago
after every eighth visit to a restaurant you receive a free beverage.after every tenth visit you receive a free appetizer. if yo
Alik [6]

On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.

  • 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
  • 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.

Thus making 40 and 80 the answers. I hope this helps!

3 0
3 years ago
A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

so that the left side condenses into the derivative of a product,

\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
Please help! Use the quadratic function to predict y if x equals 6. Y=2x^2-2x-2
iren2701 [21]
B) y=58 you follow the instructions
4 0
4 years ago
Read 2 more answers
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