-7≤ r+3 ≤+7
-7-3 ≤ r ≤ 7-3
-10 ≤ r ≤ 4
Answer:
Yes.
Step-by-step explanation:
This problem has some different steps, so lets break it down:
Ed has 12 glasses of punch with 120 milliliters of liquid contained each.
Therefore, Ed has 12 * 120 milliliters of liquid:
Now, we need to convert to liters, because that is what Ed's possible answer unit is in. Since there are 1000 milliliters in a liter, we will divide 1440 by 1000.
Thusly, Ed is correct and the answer is .
Hope this helps! Have a nice day! ((:
B
You start at 510
So 13 months is 560
14 is 610
15 is 660
16 is 710
17 is 760
18 is 810
<span>23 identical packets, consisting of 1 sheet of paper and 4 crayons.
The maximum number of packets the teacher can make from 92 crayons and 23 sheets of paper is the greatest common factor of 92 and 23. And for the values of 92 and 23, the GCF is 23.
First, calculate the list of prime numbers that when multiplied together, get each number.
23 = 23
92 = 2 * 2 * 23
Look for the largest set of prime factors in common to both numbers. In this case, it's 23.
So the teach can make 23 identical activity packets. Each packet will contain (92 / 23 = 4) crayons, and (23 / 23 = 1) sheet of paper.</span>
220-35=185
185÷2=92.5
=92.50 For each friend