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denis-greek [22]
3 years ago
13

Show that {(1,1,0),(1,0,1),(0,1,1)} is linearly independent subset of r^3

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer:  Yes, the given set of vectors is a linearly independent subset of R³.

Step-by-step explanation:  We are given to show that the following set of three vectors is a linearly independent subset of R³ :

B = {(1, 1, 0), (1, 0, 1), (0, 1, 1)} .

Since the given set contains three vectors which is equal to the dimension of R³, so it is a subset of R³.

To check the linear independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the set of vectors is linearly independent. Otherwise, it is dependent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix}1 & 1 & 0\\ 1 & 0 & 1\\ 0 & 1 & 1\end{vmatrix}\\\\\\=1(0\times1-1\times1)+1(1\times0-1\times1)+0(1\times1-0\times0)\\\\=1\times(-1)+1\times(1)+0\\\\=-1-1\\\\=-2\neq0.

Since the determinant is not equal to 0, so the given set of vectors is a linearly independent subset of R³.

Thus, the given set is a linearly independent subset of R³.

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3 0
3 years ago
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Damm [24]

Answer:

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6 0
3 years ago
A study of homeowners in the 5th congressional district in Maryland found that their annual household incomes are normally distr
tino4ka555 [31]

Answer:

The minimum income level for this target group is of $51,253.6.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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The 100 - 20 = 80th percentile, which is X when Z has a p-value of 0.8, so X when Z = 0.84.

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The minimum income level for this target group is of $51,253.6.

4 0
3 years ago
1. Is (6,7) a solution to the inequality y&gt; 2x - 5?
Zolol [24]

Answer:

\fbox{\begin{minipage}{8em}Not a solution\end{minipage}}

Step-by-step explanation:

<em>Step 1: Consider the assumption:</em>

Generally, (6, 7)) is supposed to be the pair of 2 components, in which, the first component is x-component (domain), the second component is y-component (range).

Hence, x = 6, y = 7

<em>Step 2: Substitute </em>x<em> and </em>y<em> into the inequality</em>

       y > 2x - 5

<=>  7 > 2*6 - 5

<em>Step 3: Simplify</em>

<=>  7> 12 - 5

<=>  7 > 7

<em>Step 4: Evaluate</em>

Invalid

Reason: 7 = 7

<em>Step 5: Conclude</em>

(6, 7) is not a solution to the inequality y > 2x - 5

Hope this helps!

:)

       

7 0
3 years ago
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