3 years ago

Find the formal solution of he initial value problem y'' + w^2y +

Mathematics

1 answer:

Katen [24]3 years ago

3 0

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gayaneshka [121]

Answer:

$4x + 6y^{3} x^{2}$

Step-by-step explanation:

Simplify

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1 year ago

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq

TiliK225 [7]

Answer:

The perimeter of rectangle is $18\ cm$

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

$x=y+5$ ----> equation A

$120=xy+2x^{2}+2y^{2}$ ---> equation B (area of the constructed figure)

substitute the equation A in equation B

$120=(y+5)y+2(y+5)^{2}+2y^{2}$

$120=(y+5)y+2(y+5)^{2}+2y^{2}\\ 120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\ 120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\120=5y^{2}+25y+50\\5y^{2}+25y-70=0$

using a graphing calculator -----> solve the quadratic equation

The solution is

$y=2\ cm$

Find the value of x

$x=y+5 ----> x=2+5=7\ cm$

Find the perimeter of rectangle

$P=2(x+y)=2(7+2)=18\ cm$

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3 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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