All categories

3 years ago

2.1 repeating as a mixed number?

Mathematics

1 answer:

Schach [20]3 years ago

6 0

Answer:

2 1/10

Step-by-step explanation:

"Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is 1 number to the right of the decimal point, place the decimal number over $10^{1}$ 1 (10). Next, add the whole number to the left of the decimal.

$2\frac{1}{10}$ "

quote desmos

You might be interested in

Find the area of a circle with a diameter of 16 inches. Use 3.14 for pi.

Daniel [21]

Answer:

200.96‬

Step-by-step explanation:

A = πr²

A = 3.14 x 8²

A = 3.14 x 64

A = 200.96‬

7 0

3 years ago

Read 2 more answers

An archeologist discovered two artifacts buried beneath the ground. She found the first artifact at an elevation of -8:2/7 meter

8090 [49]

Answer:

Option D is the correct choice.

Step-by-step explanation:

We are provided angle of elevations of two artifacts buried beneath the ground and we are asked to find distance between these two elevations.

We will find distance between these elevations by taking the difference of two.

$35:\frac{4}{7}--8:\frac{2}{7}$

$35:\frac{4}{7}+8:\frac{2}{7}=43:\frac{6}{7}$

Since we know that distance is always positive so option A is incorrect.

Therefore, option D is the correct choice and distance between these two elevations is $43:\frac{6}{7}$ .

5 0

3 years ago

Read 2 more answers

A square piece of fabric has an area of 16x^2+40x+25 square inches. The length of each side of the fabric is cx+d, where c and d

lozanna [386]

$A=(cx+d)^2=c^2x^2+2cdx+d^2\\\\c^2x^2+2xcd+d^2=16x^2+40x+25\\\Downarrow\\c^2=16;\ 2cd=40;\ d^2=25\\\Downarrow\\c=\sqrt{16};\ cd=20;\ d=\sqrt{25}\\\Downarrow\\\boxed{c=4\ and\ d=5}\\\\The\ length\ of\ side:cx+d=\boxed{4x+5}\\\\The\ perimeter\ of\ the\ piece\ of\ fabric:4(4x+5)=\boxed{16x+20}\\\\For\ x=2:\\16\cdot2+20=32+20=\boxed{52}$

4 0

3 years ago

What is the interval notation for the following graph

castortr0y [4]

The graph isn’t there u should put a picture of it?

8 0

3 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

4 0

2 years ago