HELP ME ASAP WORTH BRAINLEST

Mathematics

1 answer:

arlik [135]3 years ago

7 0

Footprints and trails

You might be interested in

Jackie works at two different jobs so she can buy a new car. She makes $15 per hour at her first job and $12 per hour at her sec

Inessa05 [86]

Answer:

Step-by-step explanation:

Step-by-step explanation:

$15x8=$120 = money earned at first job

$12x3=$36 = money earned at second job

$120+$36=$156 =total earned

7 0

2 years ago

Solve the formula ..........

Flauer [41]

D=rt for t
÷r both sides
d/r=t
A

3 0

3 years ago

What is the radius of a sphere with a surface area of 100πcm2?

Leona [35]

Answer:

5cm

Step-by-step explanation:

A=4πr2 = 100πcm2

r = 5

5 0

3 years ago

I need help please

galina1969 [7]

Answer:

it looks like you add the 2 than the 7

Step-by-step explanation:

yea thats it

3 0

2 years ago

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com

lora16 [44]

A)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}$

b)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}$

c)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}$

7 0

3 years ago