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3 years ago

9

Brent's neighborhood is putting down new mulch at the playground and he is in Charge of buying the mulch. One bag covers 3 yd.².

How many bags will he need?

1 answer:

Yakvenalex [24]3 years ago

7 0

Answer:

I don't know but 4 could be it

Step-by-step explanation:

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3241004551 [841]

Answer:

ok xd

Step-by-step explanation:

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3 years ago

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the length of a rectanglr exceeds its width by 5 inches, and the area is 84 square inches. what are the length and width of a a

irga5000 [103]

The area is the product of length and width, which is to say that the length and width are factors of the area.

Assuming the dimensions are integers, you want factors of 84 that differ by 5.

... 84 = 1×84 = 2×42 = 3×28 = 4×21 = 6×14 = 7×12

The last of these pairs differ by 5, so ...

the length is 12 inches
the width is 7 inches.

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3 years ago

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Solve for x. <br><br> -7x = 63

taurus [48]

Answer:

Thr answer will be -9

Divide each term by -7 and simplify

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3 years ago

18 is 13+5, and 42 is 23+19

mafiozo [28]

True... is there any specific to your question?

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3 years ago

X + 2y = 33<br> x-y = 11

Tasya [4]

Answer:

$x=\frac{55}{3},\:y=\frac{22}{3}$

Step-by-step explanation:

Solve by Substitution ;

$\begin{bmatrix}x+2y=33\\ x-y=11\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:x+2y=33:\quad x=33-2y\\\\\mathrm{Subsititute\:}x=33-2y\\\\\begin{bmatrix}33-2y-y=11\end{bmatrix}\\\\Simplify\\\begin{bmatrix}33-3y=11\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:33-3y=11:\quad y=\frac{22}{3}\\\mathrm{For\:}x=33-2y\\\\\mathrm{Subsititute\:}y=\frac{22}{3}\\x=33-2\times\frac{22}{3}\\\\x=\frac{55}{3}\\\\x=\frac{55}{3},\:y=\frac{22}{3}$

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3 years ago