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Nimfa-mama [501]
3 years ago
15

Negative 8 minus negative 4

Mathematics
1 answer:
Leokris [45]3 years ago
4 0
- 8 - (-4) = -8 + 4 = -4!
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What is the sum of the geometric series in which a1 = −5, r = 3, and an = −405?
marysya [2.9K]
An = a1 * r^(n-1)

-405 = -5*3^(n-1)

3^(n-1) = 81

3^4 = 81  so n-1 = 3  and n =  4

Sn  = S4  =  -5 (1 - 3^4)   / ( 1 - 3)   =  400 / -2 = -200 Answer
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Which number is postitive, 45, -8, -45, -8
musickatia [10]

Answer:

45

Step-by-step explanation:

if it has a subtraction or negative dash in front its negative.

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3^3 - 5 x 9 + 6 - 29
xxMikexx [17]

Answer:

-41

Step-by-step explanation:

3^3-5x9+6-29

calculate exponents 3^3=27

now write as; 27-5x9+6-29

now multiply and divide (left to right) 5x9=45

now rewrite as 27-45+6-29

now add and subtract(left to right) 27-45+6-29= -41

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Can someone help me <br> f(x) = - 7(x - 11)3(x + 13)3(x + 2)(x - 3)5
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Step-by-step explanation:

6 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
3 years ago
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