Answer:
a) x = 30°
b) mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
Question:
The complete question as found on Chegg website:
In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
intercepted have the following ratio of measurements:
mRS : mST :MTU : mUR=1:4:4:3
(a) If mRS = x, then write an equation that could be used to solve for x
and find the value of x.
(b) State the measure of each of the four arcs.
mRS =
mST =
MTU
MUR =
Step-by-step explanation:
Find attached the diagram related to the question
mRS : mST : mTU : mUR = 1:4:4:3
Since mRS = x
Writing the ratios of the measure of angle in terms of mRS:
mST = 4× mRS = 4×x = 4x
mTU = 4× mRS = 4×x = 4x
mUR= 3× mRS = 3×x = 3x
The sum of measure the 4 measures of arc = 360° (sum of angle in a circle)
mRS + mST + mTU + mUR = 360°
x + 4x + 4x + 3x = 360
12x = 360
x = 360/12
x = 30°
b) The measure of angle
mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
5.476 rounded to the hundrdths is
5.48
Answer:
(3+p)
Step-by-step explanation:
solution
first expression=9-P^2
=3^2 - P^2
=(3+P) (3-p)
second expression=p^2 + 3p
= p(3+p)
Therefore lCM= (3+p)
Answer:
228
Step-by-step explanation:
We are adding 3 each time so general rule is
Tn= 3n + 3
Therefore
T= 3(75)+3
= 228
Answer:
B) B(2,-3) and C(-2,3)
Step-by-step explanation:
The given point A, has coordinates (-2,-3).
When point A(-2,-3) is reflected over the y-axis to obtain point B, then the coordinates of B is obtained by negating the x-coordinate of A.
Therefore B will have coordinates (2,-3).
When point A(-2,-3) is reflected over the x-axis to obtain point C, then the coordinates of C is obtained by negating the y-coordinate of A.
Hence the coordinates of C are (-2,3)