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almond37 [142]
3 years ago
14

Write 3^-4 as a fraction

Mathematics
2 answers:
Lady_Fox [76]3 years ago
5 0

the numerator is three and the denominator is negative four

Ad libitum [116K]3 years ago
4 0

Answer: 1/3^4 or 1 over 3 fourths beacuse you need to just flip it to get the exponent to be positive. 3^-4 is basically 3^-4 over 1.

Step-by-step explanation:

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A down payment of 15% of the $21,200 purchase price of a new car is made. Find the amount financed.
trapecia [35]
Hello.

The answer to 1 is <span>$3,180
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6 0
3 years ago
On a coordinate grid, point T is at (2, −4) and point S is at (2, 6). The distance (in units) between points T and S is ______.
-BARSIC- [3]
The answer is 10
This is because both points have the same x value, which is 2, which means the distance between them is a straight line. That means that we can simply find the distance between the y values, and -4 to 0 is 4 units, and 0 to 6 is 6 units, so 4 + 6 = 10.

I hope this helps!
6 0
3 years ago
Read 2 more answers
Describe all of the transformations occurring as the parent function f(x) = x^3 is transformed into g(x) = -0.5(3(x+4))^3 -8
hodyreva [135]

Step-by-step explanation:

The translations of the typical functions are

y = a(bx + c)  + d

Where a is the vertical translation,

If a is greater than 1 or less than -1, we have a vertical stretch

If a is between -1 and 1 , we have a vertical compressions or shrink.

If a is negative, we have a negative reflection across the x axis.

If b is greater than 1 or less than -1, we have a horizontal compression or shrink

If b is between -1 and 1, we have a horizontal stretch

If b is negative, we have a reflection about the y axis,

If c is negative, we have a translation to the right c units

If c is positive, we have a translation to the left c units

If d is positive, we have a translation upward d units

If d is negative, we have a translation downward d units.

Here in this problem, our parent function is x^3.

So I would do the following transformations.

  • Reflect about the x axis
  • Vertical Shrink by a factor of 1/2
  • Horizontal Shrink by a factor of 3
  • Shift to the left 4 units
  • Shift downward 8 units.

4 0
2 years ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
I'LL GIVE BRAINLIEST!!
babymother [125]

Answer: 3

Step-by-step explanation:

1. 2²=4

2. 4*5=20

3. 180/20=9

4. √9=3

Hope this helped :)

4 0
3 years ago
Read 2 more answers
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