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2 years ago

Solve 5y^2+20=80, where y is the real number

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

3 0

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

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Colt1911 [192]

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2 years ago

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Rom4ik [11]

Answer:

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2 years ago

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viva [34]

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2 years ago

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expeople1 [14]

Answer:

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1 year ago

A number n plus 8 is greater than 11.

Bumek [7]

N+8>11 is the answer you are looking for

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