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3 years ago

Solve 5y^2+20=80, where y is the real number

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

3 0

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

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3 years ago

4.) solve for f(g(2))

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$f(g(2))=10$

Step-by-step explanation:

We have the two functions: $f(x)=3x-5$ and $g(x)=2+\frac{6}{x}$ .

We want to find $f(g(2))$ .

So, let's use the second function to find $g(2)$ first:

$g(2)=2+\frac{6}{2}$

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Add:

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3 years ago