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3 years ago

Solve 5y^2+20=80, where y is the real number

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

3 0

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

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grandymaker [24]

Answer:

The correct answer is B.

Step-by-step explanation:

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2 years ago

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The answer is y+5=m(x+2)

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2 years ago

-b+ 3x = C + 5b Solve for x in terms of b and c I NEED HELP

kakasveta [241]

Answer:

x = (c + 6b)/3

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra I

Combining Like Terms

Step-by-step explanation:

Step 1: Define

-b + 3x = c + 5b

Step 2: Solve for x

Add b to both sides: 3x = c + 6b
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2 years ago

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max2010maxim [7]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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