Solve 5y^2+20=80, where y is the real number

Mathematics

1 answer:

soldi70 [24.7K]4 years ago

3 0

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

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