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LUCKY_DIMON [66]
3 years ago
10

PLEASE HELP!!!!! will mark brainliest!!!!!

Mathematics
2 answers:
Liula [17]3 years ago
8 0
.............. .....................

PSYCHO15rus [73]3 years ago
5 0

Answer:

x      y

4     7

5     -1

6     -9

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The areas of the sides of a rectangular box are
Rufina [12.5K]

Answer:

<u>4900 In. Squared</u>

Step-by-step explanation:

The formula for calculating volume is Length X Base X Height

So as you can see, the way you would solve this problem si by doing

10 X 14 X 35 which would give you the final answer of

4900 Inches Squared or 4900 In.2

7 0
3 years ago
Solve 3.5x-2.8=-3.8x-7.2 graphically
pshichka [43]

x= -0.6

The graph is attached in the figure below.

Step-by-step explanation:

Solve 3.5x-2.8=-3.8x-7.2

Simplifying:

3.5x-2.8=-3.8x-7.2

Combining like terms:

3.5x+3.8x=-7.2+2.8\\7.3x=-4.4\\x=\frac{-4.4}{7.3}\\x=-0.6

x= -0.6

The graph is attached in the figure below.

Keywords: Graph the equation

Learn more about Graphing the equation at:

  • brainly.com/question/12967961
  • brainly.com/question/10879401
  • brainly.com/question/3126500

#learnwithBrainly

3 0
3 years ago
Explain how to use equivalent ratios to find 125% of 200.
ikadub [295]
125 of 200 can be wriiten as:
125
200
Multiply both numerator & denominator by 100

125
200
×
100
100
=
62.5
100
= 62.5%
If you are using a calculator, simply enter 125÷200×100 which will give you 62.5 as the answer.
7 0
4 years ago
Read 2 more answers
In an average month, Jaden sends 200 texts and talks for 100 minutes. Give the cost for plan A and for plan B. Then tell which p
amid [387]

Answer:

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Step-by-step explanation:

Let's calculate the amount required for each plan

<h3>Plan A</h3>
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<h3>Plan B</h3>
  • 15 + 200*0.05 + 100*0.05 =  $30

As we see Plan B costs less

8 0
3 years ago
The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample
dem82 [27]

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.

7 0
4 years ago
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