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Elena-2011 [213]
3 years ago
12

6 times the sum of y and 11

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

6y+66

Step-by-step explanation:

write the problem out, placing 6 on its own, and the sum of y and 11 inside a pair of parentheses after the 6.

6(y+11)

then, just use the distributive property and multiply each term inside the coefficients by six. you'll get 6y+66 as your final answer.

if your teacher says that the final answer is not supposed to have variables in it, then we'll need a bit more information.

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
Simplify the expression: 8–3w+3w+2–8
Ray Of Light [21]
Combine like terms. 3w-3w=0. 8+2-8=2. So the answer is 2. I hope this helps!
4 0
3 years ago
Anyone know how to do this? (10)
Hatshy [7]
MP = P - M = (0, 5) - (5, 6) = (0-5, 5-6) = (-5, -1) |MP| = √((-5)^2 + (-1)^2) = √(25+1) = √26
6 0
3 years ago
Read 2 more answers
HELP NOW PLEASE is say for each pair of angle in parts A thought D estimate the measure of each angle.
Mice21 [21]

Answer: A: V is an acute angle, so it is less than 90 degrees. I would say it's around 45 degrees.

B: K is also an acute angle, but it is fairly close to being 90 degrees, so I'd say around 80 degrees.

C:  Q is an obtuse angle, so it is over 90 degrees but less than 180 degrees. I would say it's around 110 degrees.

D: Y is an obtuse angle. It is very close to 180 degrees. I would say it's around 160 degrees.

Step-by-step explanation:


3 0
3 years ago
Please help me with this question!
IrinaVladis [17]
You could do 4^5 or 1024
6 0
3 years ago
Read 2 more answers
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