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Elena-2011 [213]
3 years ago
12

6 times the sum of y and 11

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

6y+66

Step-by-step explanation:

write the problem out, placing 6 on its own, and the sum of y and 11 inside a pair of parentheses after the 6.

6(y+11)

then, just use the distributive property and multiply each term inside the coefficients by six. you'll get 6y+66 as your final answer.

if your teacher says that the final answer is not supposed to have variables in it, then we'll need a bit more information.

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-94 ...nagative 94

Step-by-step explanation:

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A fuel tank contains 1 3/4 gallons of gasoline. Casey adds 33 1/3 gallons of gasoline to the tank. How many gallons of gas does
krek1111 [17]

Answer:

35 1/12 gallons of gasoline

Step-by-step explanation:

so what you're going to do is take both of the fractions (3/4 and 1/3) and convert them into two fractions with the same denominator so you can add them easily. the closest number that you can convert them to would be a denominator of 12, so we would turn 3/4 into its equivalent of 9/12 and 1/3 would now be 4/12. now we add them and get 13/12, which is an improper fraction, so we would change that to 1 and 1/12. and finally, we add 1 1/12 + 1 + 33 and we would get 35 and 1/12 as our final answer :)

6 0
3 years ago
Answer please show steps please
erik [133]

Answer:

25 girls

Step-by-step explanation:

Let

x denote number of boys

and

y denote number of girls

According to the statement that total 45 people came,

x+y = 45      => Eqn 1

And total paid amount was 175

So,

5x + 3y = 175    => Eqn 2

For solving, We will use the substitution method

So, from eqn 1

x = 45-y

Putting value of x in eqn 2

5(45-y) +3y = 175

225 - 5y + 3y = 175

-2y+225 = 175

-2y = 175-225

-2y = -50

2y = 50

y = 25

Putting y =25 in eqn 1

x+25 = 45

x = 45 - 25

x = 20

As y= 25

So, 25 girls came to the dance ..

6 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
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