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2 years ago

6 times the sum of y and 11

Mathematics

1 answer:

Gelneren [198K]2 years ago

4 0

Answer:

6y+66

Step-by-step explanation:

write the problem out, placing 6 on its own, and the sum of y and 11 inside a pair of parentheses after the 6.

6(y+11)

then, just use the distributive property and multiply each term inside the coefficients by six. you'll get 6y+66 as your final answer.

if your teacher says that the final answer is not supposed to have variables in it, then we'll need a bit more information.

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What’s the answer for 5y-y=3y + 2

antiseptic1488 [7]

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Step-by-step explanation:

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2 years ago

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vesna_86 [32]

Answer:

$f(x) = 3(x -\frac{2}{3})^2 -\frac{22}{3}$

The vertex is $(\frac{2}{3}, -\frac{22}{3})$

Step-by-step explanation:

For a general quadratic function the form is:

$ax ^ 2 + bx + c$

For the function

$f(x) = 3x ^ 2 -4x -6$

Take common factor 3.

$f(x) = 3(x ^ 2 -\frac{4}{3}x - 2)$

The values of the coefficients for the function within the parenthesis are the following: $a = 1$ , $b = -\frac{4}{3}$ , $c = -2$

Take the value of b and divide it by 2. Then, the result obtained squares it.

$\frac{b}{2}= -\frac{2}{3}$

$(\frac{b}{2})^2=\frac{4}{9}$

Add and subtract $\frac{4}{9}$

$f(x) = 3([x ^ 2 -\frac{4}{3}x +\frac{4}{9}]- 2-\frac{4}{9})$

Write the expression of the form

$f(x) = (x-\frac{b}{2})^2 +k$

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2 years ago

(−14x^3y^3+4x^5 y6)÷(2x^4y^5)

valkas [14]

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= 4x^5y^6 - 14x^3y^3/2x^4y^5

= 4x^2y^3 - 14/2xy^2

= 2x^2y^3 - 7/xy^2

Answer: 2x^2y^3 - 7/xy^2

Hope that helps!!!!

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Step-by-step explanation:

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