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Ray Of Light [21]
3 years ago
8

20 POINTS

Mathematics
1 answer:
quester [9]3 years ago
4 0

Answer:

C

Step-by-step explanation:

7 * 2 is 14 + 6 is equal to 20. That is the only possible answer.

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What is the simplification of (-2x+4) + 2(2x+1)
melomori [17]
(-2x+4)+2(2x+1)= -2(-x-3)
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3 years ago
You are driving in Canada and the speed limit is 110 kph (kilometers per hour). How fast is that in mph (miles per hour)?
Karo-lina-s [1.5K]
The answer is 68 mph. Hope this helps :)
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3 years ago
Write a quadratic equation in standard form with the given roots
stich3 [128]

{x}^{2}  -  \frac{15x}{2}   +  \frac{7}{2}

Step-by-step explanation:

So we go backwards, since we have x= 1/2 , 7

(x -  \frac{1}{2} )(x - 7)

Now we have to foil to get the quadratic

{x}^{2}  - 7x -  \frac{1}{2} x +  \frac{7}{2}

We must simplify the terms

{x}^{2}  -  \frac{14x}{2}  -  \frac{x}{2}  +  \frac{7}{2}

Our final result comes out to be

{x}^{2}  -  \frac{15x}{2}   +  \frac{7}{2}

5 0
2 years ago
∠1 and ∠2 are complementary angles. m∠1 is 5y+32 and m∠2 is 7y-14. Find m∠2 & show your work.
Ainat [17]
  • m<1+m<2=90

\\ \sf\longmapsto 5y+32+7y-14=90

\\ \sf\longmapsto 12y+18=90

\\ \sf\longmapsto 12y=72

\\ \sf\longmapsto y=6

  • m<2=7(6)-14=42-14=28[/tex]
7 0
3 years ago
Read 2 more answers
Jasmine is designing boxes she will use to ship her jewelry. She wants to shape the box like a regular polygon. In order for the
Naddik [55]

Answer:

The regular polygon that she should use is an equilateral  triangle

Step-by-step explanation:

The parameters given are;

Interior angles = 0.5 × Exterior angles

Exterior angles of a regular polygon = 360/n

Sum of interior angles of a regular polygon = (n - 2) × 180

Where n = the number of sides

Therefore, the sum of exterior angles of a regular polygon = 360°

Hence we have;

(n - 2) × 180 = 360/2 = 180

n - 2 = 180/180 = 1

n = 1 + 2 = 3 which is a three sided regular polygon or an equilateral triangle

Therefore, the regular polygon that she should use is an equilateral  triangle

3 0
4 years ago
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