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dybincka [34]
3 years ago
15

The graph of the function f(x)= 2x is shown. The inverse is also a function. If the domain of the inverse is the range values of

the original function, identify the domain of the inverse of f(x).
A) {any real number}
B) {any real number > 0}
C) {any real number < 0}
D) {any real number ≥ 0}
Mathematics
2 answers:
boyakko [2]3 years ago
5 0

Answer:

actually its B {any real number > 0

NNADVOKAT [17]3 years ago
3 0
D. {any real number > 0}
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3 years ago
Which of the following are solutions?
zloy xaker [14]

This is a quadratic equation. There's a shortcut (two shortcuts really) called the Shakespeare Quadratic Formula (2b or -2b) applicable when the middle term is even:

x^2 - 2bx + c \textrm{ has zeros } x= b\pm \sqrt{b^2-c}

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OK, our problem is

9x^2 - 6x -7 = 0

x = \frac 1 9 (3 \pm \sqrt{9-(9)(-7)}) = \frac 1 9(3 \pm \sqrt{72})= \frac 1 9(3 \pm 3 \sqrt{8}) = \frac 1 3(1 \pm \sqrt 8)

Typically we'd write \sqrt 8 = 2 \sqrt 2 but the answers here don't so we won't either.

Answer: C and D

7 0
3 years ago
Four more than the quotient of a number,n,and 8 is 28
strojnjashka [21]
N/8+4=28.
This is how you write out this equation.
5 0
3 years ago
Given that cos 63°≈ 0.454, enter the sine of a complementary angle.<br> sin
jek_recluse [69]

Answer:

\cos(63^\circ) is the same as \sin(27^\circ) by co-function identities

Step-by-step explanation:

Remember that complementary angles add up to 90°. The angle that i s complementary to 63° is 27°.

Also recall the co-function identities:

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This means that \cos(90^\circ-27^\circ)=\sin(27^\circ)\approx0.454.

4 0
2 years ago
Expressions cannot _____.
Gwar [14]
Expressions cannot <u>be solved.
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8 0
3 years ago
Read 2 more answers
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