Split up the interval [1, 9] into <em>n</em> subintervals of equal length (9 - 1)/<em>n</em> = 8/<em>n</em> :
[1, 1 + 8/<em>n</em>], [1 + 8/<em>n</em>, 1 + 16/<em>n</em>], [1 + 16/<em>n</em>, 1 + 24/<em>n</em>], …, [1 + 8 (<em>n</em> - 1)/<em>n</em>, 9]
It should be clear that the left endpoint of each subinterval make up an arithmetic sequence, so that the <em>i</em>-th subinterval has left endpoint
1 + 8/<em>n</em> (<em>i</em> - 1)
Then we approximate the definite integral by the sum of the areas of <em>n</em> rectangles with length 8/<em>n</em> and height
:

Take the limit as <em>n</em> approaches infinity and the approximation becomes exact. So we have

Answer: The length is 3 times bigger than the other length.
Step-by-step explanation:
Answer: - 6 1/2
Step-by-step explanation:
We should note that:
=-4 - 2 1/2
= -6 1/2
For example, let's assume you owe Bob $4 and then you owe Bill $2 1/2. To calculate the total amount owed, you would have $6 1/2.
16 blocks = 4 steps
x blocks = 50 steps
(16 blocks x 50 steps)/4 steps
= 200 blocks